![]() ![]() And finally here as well, let's blufgan the Sign 25. ![]() And also we know that the final velocity is zero because the maximum height is when the block stops moving completely. And here the angle is co sign 180 Which is basically -1. The work done is only due to the frictional force multiplied by the distance it goes upwards, multiplied by cosign the angle between the frictional force and the motion. And let's substitute here for the work done. The change that block will go higher, Then its initial position with a value of design 25 and all of this is again equal to the work done. The change in height of this block here will be this distance showed here, shown here, and this is equal to the distance it goes uphill sign 25. And the change in the potential energy is equal to M. The change in the kinetic energy is equal to have multiplied by em, multiplied by the final velocity squared minus the initial velocity squared. So the change in energy is the change in both the kinetic energy and the potential energy. The change in total energy is equal to the work done on the object. That's the first step in calculating the distance. From this we have the frictional force equal to open 667 Newtons. So from here we have opened 15, multiplied by M. Now the frictional force is equal to the coefficient of friction, multiplied by the normal force. And the normal for girls will be equal to this value. And from this here we have that this force perpendicular to the plane is MG. And here we have this angle is equal to This angle, so both are equal to 25. We need to get the normal force and to get the normal force here we have that's the weight, which is M. So we know how to calculate the frictional force. So the question is to determine the value of the or to catholic, how far will this block go up? So first let's start by getting the friction of force that is applied on this block here because this is the force that will be doing work against this block here. And the friction of coefficient Of this surface here is 0.15. So here, if this block stops after a distance D. And this problem we have a block that has given an initial chart up this incline here and this incline makes an angle of 25 with the horizon here, The block weighs 500 g And it's given an initial velocity of 200 centimetres per second. SOLVED:A 500 -g block is shot up the incline in \underline$. ![]()
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